The internal storage of a DATETIME value
SELECT [Now],
BinaryFormat,
SUBSTRING(BinaryFormat, 1, 4) AS DayPart,
SUBSTRING(BinaryFormat, 5, 4) AS TimePart,
CAST(SUBSTRING(BinaryFormat, 1, 4) AS INT) AS [Days],
DATEADD(DAY, CAST(SUBSTRING(BinaryFormat, 1, 4) AS INT), 0) AS [Today],
CAST(SUBSTRING(BinaryFormat, 5, 4) AS INT) AS [Ticks],
DATEADD(MILLISECOND, 1000.E / 300.E * CAST(SUBSTRING(BinaryFormat, 5, 4) AS INT), 0) AS Peso
FROM (
SELECT GETDATE() AS [Now],
CAST(GETDATE() AS BINARY(8)) AS BinaryFormat
) AS d
Legacy Comments
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Naomi
2011-07-07 |
re: The internal storage of a DATETIME value How are you going to convert int value into datetime? |
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Peso
2011-07-07 |
re: The internal storage of a DATETIME value You mean an INT like 20110707? Not easily since an integer doesn't follow 12 month rule per year. |
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a good thesis from Essay 24/7
2012-08-28 |
re: The internal storage of a DATETIME value This post might be a good read if you just posted some description on the codes you wrote here. |