This is nothing new to me (I come across this autumn 2007) and probably not to you either but I forgot about it and yesterday it came alive again. I often choose a table variable for performance reasons (if data is less than 1 page anyway) due to the benefits of no logging etc etc.
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Yesterday Joe Celko posted on microsoft.public.sqlserver.programming about how to write an elegant query for Weighted Median. He managed to get the correct results but always ended up with ugly code. Joe had a feeling an elegant query existed but was not seeing it.
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For more information about my SQLCLR, see http://www.developerworkshop.net/software.html The biggest difference from Beta2 stage is that I now only target SQL Server 2008 and later. //Peso
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The answer to your question is "Yes, I am having a slow day today."
;WITHFibonacci(n, f, f1) AS ( SELECT CAST(1 AS BIGINT), CAST(0 AS BIGINT), CAST(1 AS BIGINT) UNION ALL SELECT n + 1, f + f1, f FROM Fibonacci WHERE n < 93 ) SELECTn, f AS Number FROMFibonacci
Legacy Comments
Liam Caffrey
2009-08-27
re: Recursive Fibonacci number calculation Hi,
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Here is a simple base converter that manages [from and to] base 2 to 16. CREATEFUNCTION dbo.fnBaseConvert ( @Value VARCHAR(8), @FromBase TINYINT, @ToBase TINYINT ) RETURNSVARCHAR(32) AS BEGIN RETURN ( SELECT SUBSTRING('0123456789abcdef', 1 +(x.
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Since this blog post http://weblogs.sqlteam.com/peterl/archive/2007/09/24/Finding-group-of-records-with-a-certain-status.aspx I have kept the technique in similar situations and perhaps never bothered to rethink my prerogative. Well, today I have. Recently I blogged here http://weblogs.
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Here http://weblogs.sqlteam.com/peterl/archive/2009/07/12/How-to-calculate-the-number-of-weekdays-in-a-month.aspx is a specialized version for a month, and here http://weblogs.sqlteam.com/peterl/archive/2009/07/12/How-to-calculate-number-of-weekdays-in-a-year.aspx is a specialized version for a year. This code below calculates the number of weekdays for any given period.
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It seems JDEdwards dates are stored NUMERIC(6, 0) in this format 107299, where 107 is the number of years after 1900, and 299 is the 299th day of the year. So how to convert JDEdwards to DATETIME?
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I've posted a feedback on Microsoft Connect about how to enhance the INSERT INTO syntax. Especially for INSERT INTO ... EXEC ... Sometimes when you need the result from a stored procedure, the SP itself returns two (or more) resultsets.
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Recently I posted a function which returned the Nth weekday of a month, either from the beginning of month or from the end of month. Function is found here http://weblogs.sqlteam.com/peterl/archive/2009/06/17/How-to-get-the-Nth-weekday-of-a-month.aspx I have fiddled around with it and have now extended the function to find the Nth weekday not only for a month, but also for a quarter or a year.
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You call this function with a date. The function returns a table with one record and 3 columns. First column is Weekday; Monday = 1, Tuesday = 2, Wednesday = 3; Thursday = 4, Friday = 5, Saturday = 6 and Sunday = 7.
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You call this function with three parameters: 1. Any date of the month in question 2. The weekday to calculate; Monday 1, Tuesday 2, Wednesday 3, Thursday 4, Friday 5, Saturday 6 and Sunday 7 3.
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I did some tests today to measure the different approaches for finding records present in one table but not in another. The results of CPU and Duration are presented below with some help from SQL Profiler.
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For some time ago, I posted an algorithm how to get the XML structure automatically. Today I stumbled across another approach which seems to be faster. Reservations though I haven't tested this against large xml data yet.
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Wow! This seems to be blog post number 100. Today I stumbled across an interesting problem where OP had a set of records. Every record were "typed" and "grouped". Now OP wanted to get distinct group id's for those groups having at least one record typed 33, but not having a record typed 11.
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With the arrival of SQL Server 2005 the new OUTPUT operator was introduced. The OUTPUT operator works much like a "local trigger" on the current statement. The drawback is that there is no way to filter the returned resultset directly.
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I previously posted a solution for one variable here http://weblogs.sqlteam.com/peterl/archive/2009/03/11/Excel-ERF-clone.aspx and here is a solution for using two variables. CREATEFUNCTION dbo.fnErf ( @z1 FLOAT, @z2 FLOAT, @MaxIterations TINYINT = 10 ) RETURNSFLOAT AS BEGIN IF @z1 IS NULL OR @z2 IS NULL RETURN NULL DECLARE @n TINYINT, @s1 FLOAT, @s2 FLOAT, @p1 FLOAT, @p2 FLOAT, @a1 FLOAT, @a2 FLOAT SELECT @n = 1, @p1 = 1, @p2 = 1, @a1 = @z1, @a2 = @z2, @MaxIterations = COALESCE(ABS(@MaxIterations), 10) WHILE @p1 <> 0.
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Today I am going to talk about how to efficiently reuse identity values in a column, even if this is something that normally not should be bothered. The reason for this solution was a request for help from a member here on SQLTeam, who was near run out of identity values.
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Adam Machanic has a nice competition going on here http://sqlblog.com/blogs/adam_machanic/archive/2009/02/27/t-sql-challenge-grouped-string-concatenation.aspx until the 16th of March 2009.
Please join in! The prize, for the best submission, is a full MSDN subscription, valued at around $10,000.
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CREATEFUNCTION dbo.fnIsLeapYear ( @Year SMALLINT ) RETURNSBIT AS BEGIN RETURN CASE DATEPART(DAY, DATEADD(YEAR, @Year - 1904, '19040229')) WHEN29 THEN 1 ELSE 0 END END
Legacy Comments
Brian Tkatch
2009-02-25
re: Fastest LeapYear checker?
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